-12(y+2)+4(4y-7)=3(y-4)+13

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Solution for -12(y+2)+4(4y-7)=3(y-4)+13 equation: 



-12(y+2)+4(4y-7)=3(y-4)+13

We move all terms to the left:

-12(y+2)+4(4y-7)-(3(y-4)+13)=0

We multiply parentheses

-12y+16y-(3(y-4)+13)-24-28=0



We calculate terms in parentheses: -(3(y-4)+13), so:

3(y-4)+13

We multiply parentheses

3y-12+13

We add all the numbers together, and all the variables

3y+1

Back to the equation:

-(3y+1)



We add all the numbers together, and all the variables

4y-(3y+1)-52=0

We get rid of parentheses

4y-3y-1-52=0

We add all the numbers together, and all the variables

y-53=0

We move all terms containing y to the left, all other terms to the right

y=53

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