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(8x-5x-1)=(8x-5x-1)
We move all terms to the left:
(8x-5x-1)-((8x-5x-1))=0
We add all the numbers together, and all the variables
(3x-1)-((3x-1))=0
We get rid of parentheses
3x-((3x-1))-1=0
We calculate terms in parentheses: -((3x-1)), so:We get rid of parentheses
(3x-1)
We get rid of parentheses
3x-1
Back to the equation:
-(3x-1)
3x-3x+1-1=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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