6(16-x)-9(25-2x)=28(x-3)+3

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Solution for 6(16-x)-9(25-2x)=28(x-3)+3 equation: 



6(16-x)-9(25-2x)=28(x-3)+3

We move all terms to the left:

6(16-x)-9(25-2x)-(28(x-3)+3)=0

We add all the numbers together, and all the variables

6(-1x+16)-9(-2x+25)-(28(x-3)+3)=0

We multiply parentheses

-6x+18x-(28(x-3)+3)+96-225=0



We calculate terms in parentheses: -(28(x-3)+3), so:

28(x-3)+3

We multiply parentheses

28x-84+3

We add all the numbers together, and all the variables

28x-81

Back to the equation:

-(28x-81)



We add all the numbers together, and all the variables

12x-(28x-81)-129=0

We get rid of parentheses

12x-28x+81-129=0

We add all the numbers together, and all the variables

-16x-48=0

We move all terms containing x to the left, all other terms to the right

-16x=48

x=48/-16

x=-3

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