(8x-5)=(65-2x)

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Solution for (8x-5)=(65-2x) equation: 



(8x-5)=(65-2x)

We move all terms to the left:

(8x-5)-((65-2x))=0

We add all the numbers together, and all the variables

(8x-5)-((-2x+65))=0

We get rid of parentheses

8x-((-2x+65))-5=0



We calculate terms in parentheses: -((-2x+65)), so:

(-2x+65)

We get rid of parentheses

-2x+65

Back to the equation:

-(-2x+65)



We get rid of parentheses

8x+2x-65-5=0

We add all the numbers together, and all the variables

10x-70=0

We move all terms containing x to the left, all other terms to the right

10x=70

x=70/10

x=7

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