2(9-2x)-x=3(3x-2)-4

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Solution for 2(9-2x)-x=3(3x-2)-4 equation: 



2(9-2x)-x=3(3x-2)-4

We move all terms to the left:

2(9-2x)-x-(3(3x-2)-4)=0

We add all the numbers together, and all the variables

2(-2x+9)-x-(3(3x-2)-4)=0

We add all the numbers together, and all the variables

-1x+2(-2x+9)-(3(3x-2)-4)=0

We multiply parentheses

-1x-4x-(3(3x-2)-4)+18=0



We calculate terms in parentheses: -(3(3x-2)-4), so:

3(3x-2)-4

We multiply parentheses

9x-6-4

We add all the numbers together, and all the variables

9x-10

Back to the equation:

-(9x-10)



We add all the numbers together, and all the variables

-5x-(9x-10)+18=0

We get rid of parentheses

-5x-9x+10+18=0

We add all the numbers together, and all the variables

-14x+28=0

We move all terms containing x to the left, all other terms to the right

-14x=-28

x=-28/-14

x=+2

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