(8x-31)+(6x-8)=(10x+17)

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Solution for (8x-31)+(6x-8)=(10x+17) equation: 



(8x-31)+(6x-8)=(10x+17)

We move all terms to the left:

(8x-31)+(6x-8)-((10x+17))=0

We get rid of parentheses

8x+6x-((10x+17))-31-8=0



We calculate terms in parentheses: -((10x+17)), so:

(10x+17)

We get rid of parentheses

10x+17

Back to the equation:

-(10x+17)



We add all the numbers together, and all the variables

14x-(10x+17)-39=0

We get rid of parentheses

14x-10x-17-39=0

We add all the numbers together, and all the variables

4x-56=0

We move all terms containing x to the left, all other terms to the right

4x=56

x=56/4

x=14

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