(2x+22)+(4x+11)=(9x-15)

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Solution for (2x+22)+(4x+11)=(9x-15) equation: 



(2x+22)+(4x+11)=(9x-15)

We move all terms to the left:

(2x+22)+(4x+11)-((9x-15))=0

We get rid of parentheses

2x+4x-((9x-15))+22+11=0



We calculate terms in parentheses: -((9x-15)), so:

(9x-15)

We get rid of parentheses

9x-15

Back to the equation:

-(9x-15)



We add all the numbers together, and all the variables

6x-(9x-15)+33=0

We get rid of parentheses

6x-9x+15+33=0

We add all the numbers together, and all the variables

-3x+48=0

We move all terms containing x to the left, all other terms to the right

-3x=-48

x=-48/-3

x=+16

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