3x+2=x+4(x-2)

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Solution for 3x+2=x+4(x-2) equation: 



3x+2=x+4(x-2)

We move all terms to the left:

3x+2-(x+4(x-2))=0



We calculate terms in parentheses: -(x+4(x-2)), so:

x+4(x-2)

We multiply parentheses

x+4x-8

We add all the numbers together, and all the variables

5x-8

Back to the equation:

-(5x-8)



We get rid of parentheses

3x-5x+8+2=0

We add all the numbers together, and all the variables

-2x+10=0

We move all terms containing x to the left, all other terms to the right

-2x=-10

x=-10/-2

x=+5

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