(8x-3)(7x+8)=0

Solution for (8x-3)(7x+8)=0 equation:

(8x-3)(7x+8)=0

We multiply parentheses ..

(+56x^2+64x-21x-24)=0

We get rid of parentheses

56x^2+64x-21x-24=0

We add all the numbers together, and all the variables

56x^2+43x-24=0

a = 56; b = 43; c = -24;
Δ = b2-4ac
Δ = 432-4·56·(-24)
Δ = 7225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7225}=85$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(43)-85}{2*56}=\frac{-128}{112}
=-1+1/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(43)+85}{2*56}=\frac{42}{112}
=3/8
$