15x2-44x+21=0

Solution for 15x2-44x+21=0 equation:

15x^2-44x+21=0

a = 15; b = -44; c = +21;
Δ = b2-4ac
Δ = -442-4·15·21
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-26}{2*15}=\frac{18}{30}
=3/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+26}{2*15}=\frac{70}{30}
=2+1/3
$