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(8x-29)=(3x-1)=(6x-11)
We move all terms to the left:
(8x-29)-((3x-1))=0
We get rid of parentheses
8x-((3x-1))-29=0
We calculate terms in parentheses: -((3x-1)), so:We get rid of parentheses
(3x-1)
We get rid of parentheses
3x-1
Back to the equation:
-(3x-1)
8x-3x+1-29=0
We add all the numbers together, and all the variables
5x-28=0
We move all terms containing x to the left, all other terms to the right
5x=28
x=28/5
x=5+3/5
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