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(8x-29)=(3x-1)(6x-11)
We move all terms to the left:
(8x-29)-((3x-1)(6x-11))=0
We get rid of parentheses
8x-((3x-1)(6x-11))-29=0
We multiply parentheses ..
-((+18x^2-33x-6x+11))+8x-29=0
We calculate terms in parentheses: -((+18x^2-33x-6x+11)), so:We add all the numbers together, and all the variables
(+18x^2-33x-6x+11)
We get rid of parentheses
18x^2-33x-6x+11
We add all the numbers together, and all the variables
18x^2-39x+11
Back to the equation:
-(18x^2-39x+11)
8x-(18x^2-39x+11)-29=0
We get rid of parentheses
-18x^2+8x+39x-11-29=0
We add all the numbers together, and all the variables
-18x^2+47x-40=0
a = -18; b = 47; c = -40;
Δ = b2-4ac
Δ = 472-4·(-18)·(-40)
Δ = -671
Delta is less than zero, so there is no solution for the equation
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