(8x-29)+(3x-1)=(6x-11)

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Solution for (8x-29)+(3x-1)=(6x-11) equation: 



(8x-29)+(3x-1)=(6x-11)

We move all terms to the left:

(8x-29)+(3x-1)-((6x-11))=0

We get rid of parentheses

8x+3x-((6x-11))-29-1=0



We calculate terms in parentheses: -((6x-11)), so:

(6x-11)

We get rid of parentheses

6x-11

Back to the equation:

-(6x-11)



We add all the numbers together, and all the variables

11x-(6x-11)-30=0

We get rid of parentheses

11x-6x+11-30=0

We add all the numbers together, and all the variables

5x-19=0

We move all terms containing x to the left, all other terms to the right

5x=19

x=19/5

x=3+4/5

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