(3x-4)=(6x+13)

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Solution for (3x-4)=(6x+13) equation: 



(3x-4)=(6x+13)

We move all terms to the left:

(3x-4)-((6x+13))=0

We get rid of parentheses

3x-((6x+13))-4=0



We calculate terms in parentheses: -((6x+13)), so:

(6x+13)

We get rid of parentheses

6x+13

Back to the equation:

-(6x+13)



We get rid of parentheses

3x-6x-13-4=0

We add all the numbers together, and all the variables

-3x-17=0

We move all terms containing x to the left, all other terms to the right

-3x=17

x=17/-3

x=-5+2/3

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