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(8x-1)/(4x+1)=5
We move all terms to the left:
(8x-1)/(4x+1)-(5)=0
Domain of the equation: (4x+1)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
4x!=-1
x!=-1/4
x!=-1/4
x∈R
(8x-1)-5*(4x+1)=0
We multiply parentheses
(8x-1)-20x-5=0
We get rid of parentheses
8x-20x-1-5=0
We add all the numbers together, and all the variables
-12x-6=0
We move all terms containing x to the left, all other terms to the right
-12x=6
x=6/-12
x=-1/2
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