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30x=5x(x-6)
We move all terms to the left:
30x-(5x(x-6))=0
We calculate terms in parentheses: -(5x(x-6)), so:We get rid of parentheses
5x(x-6)
We multiply parentheses
5x^2-30x
Back to the equation:
-(5x^2-30x)
-5x^2+30x+30x=0
We add all the numbers together, and all the variables
-5x^2+60x=0
a = -5; b = 60; c = 0;
Δ = b2-4ac
Δ = 602-4·(-5)·0
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-60}{2*-5}=\frac{-120}{-10} =+12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+60}{2*-5}=\frac{0}{-10} =0 $
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