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(8x-1)(6x+2)=0
We multiply parentheses ..
(+48x^2+16x-6x-2)=0
We get rid of parentheses
48x^2+16x-6x-2=0
We add all the numbers together, and all the variables
48x^2+10x-2=0
a = 48; b = 10; c = -2;
Δ = b2-4ac
Δ = 102-4·48·(-2)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-22}{2*48}=\frac{-32}{96} =-1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+22}{2*48}=\frac{12}{96} =1/8 $
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