(8x+2)(4x+10)-(180)=0

Solution for (8x+2)(4x+10)-(180)=0 equation:

(8x+2)(4x+10)-(180)=0

We multiply parentheses ..

(+32x^2+80x+8x+20)-180=0

We get rid of parentheses

32x^2+80x+8x+20-180=0

We add all the numbers together, and all the variables

32x^2+88x-160=0

a = 32; b = 88; c = -160;
Δ = b2-4ac
Δ = 882-4·32·(-160)
Δ = 28224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{28224}=168$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(88)-168}{2*32}=\frac{-256}{64}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(88)+168}{2*32}=\frac{80}{64}
=1+1/4
$