(8x+1)/3-(5-4x)/4=-1-4(3x-2)/3

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Solution for (8x+1)/3-(5-4x)/4=-1-4(3x-2)/3 equation: 



(8x+1)/3-(5-4x)/4=-1-4(3x-2)/3

We move all terms to the left:

(8x+1)/3-(5-4x)/4-(-1-4(3x-2)/3)=0

We add all the numbers together, and all the variables

(8x+1)/3-(-4x+5)/4-(-1-4(3x-2)/3)=0

We calculate fractions


(32x+4)/()+4x/()+(-(-1-4(3x-2)*4)/()=0



We calculate terms in parentheses: +(-(-1-4(3x-2)*4)/(), so:

-(-1-4(3x-2)*4)/(

We multiply all the terms by the denominator


-(-1-4(3x-2)*4)



We calculate terms in parentheses: -(-1-4(3x-2)*4), so:

-1-4(3x-2)*4

determiningTheFunctionDomain
-4(3x-2)*4-1

We multiply parentheses

-48x+32-1

We add all the numbers together, and all the variables

-48x+31

Back to the equation:

-(-48x+31)



We get rid of parentheses

48x-31

Back to the equation:

+(48x-31)



We get rid of parentheses

(32x+4)/()+4x/()+48x-31=0

We multiply all the terms by the denominator


(32x+4)+4x+48x*()-31*()=0

We add all the numbers together, and all the variables

4x+(32x+4)+48x*()=0

We get rid of parentheses

4x+32x+48x*()+4=0

We add all the numbers together, and all the variables

36x+48x*()+4=0

We move all terms containing x to the left, all other terms to the right

36x+48x*()=-4

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