5(a+3)+(a+1)=4

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Solution for 5(a+3)+(a+1)=4 equation: 



5(a+3)+(a+1)=4

We move all terms to the left:

5(a+3)+(a+1)-(4)=0

We multiply parentheses

5a+(a+1)+15-4=0

We get rid of parentheses

5a+a+1+15-4=0

We add all the numbers together, and all the variables

6a+12=0

We move all terms containing a to the left, all other terms to the right

6a=-12

a=-12/6

a=-2

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