(8x+1)+(9x+1)=(7x+3)+(8x+5)

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Solution for (8x+1)+(9x+1)=(7x+3)+(8x+5) equation: 



(8x+1)+(9x+1)=(7x+3)+(8x+5)

We move all terms to the left:

(8x+1)+(9x+1)-((7x+3)+(8x+5))=0

We get rid of parentheses

8x+9x-((7x+3)+(8x+5))+1+1=0



We calculate terms in parentheses: -((7x+3)+(8x+5)), so:

(7x+3)+(8x+5)

We get rid of parentheses

7x+8x+3+5

We add all the numbers together, and all the variables

15x+8

Back to the equation:

-(15x+8)



We add all the numbers together, and all the variables

17x-(15x+8)+2=0

We get rid of parentheses

17x-15x-8+2=0

We add all the numbers together, and all the variables

2x-6=0

We move all terms containing x to the left, all other terms to the right

2x=6

x=6/2

x=3

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