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2(2x+4)=(2x+3)+(2x+4)
We move all terms to the left:
2(2x+4)-((2x+3)+(2x+4))=0
We multiply parentheses
4x-((2x+3)+(2x+4))+8=0
We calculate terms in parentheses: -((2x+3)+(2x+4)), so:We get rid of parentheses
(2x+3)+(2x+4)
We get rid of parentheses
2x+2x+3+4
We add all the numbers together, and all the variables
4x+7
Back to the equation:
-(4x+7)
4x-4x-7+8=0
We add all the numbers together, and all the variables
1!=0
There is no solution for this equation
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