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(8x+1)(8x+1)=0
We multiply parentheses ..
(+64x^2+8x+8x+1)=0
We get rid of parentheses
64x^2+8x+8x+1=0
We add all the numbers together, and all the variables
64x^2+16x+1=0
a = 64; b = 16; c = +1;
Δ = b2-4ac
Δ = 162-4·64·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-16}{128}=-1/8$
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