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(8x)=(2x+60)
We move all terms to the left:
(8x)-((2x+60))=0
We calculate terms in parentheses: -((2x+60)), so:We get rid of parentheses
(2x+60)
We get rid of parentheses
2x+60
Back to the equation:
-(2x+60)
8x-2x-60=0
We add all the numbers together, and all the variables
6x-60=0
We move all terms containing x to the left, all other terms to the right
6x=60
x=60/6
x=10
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