(8h-3)(4h-7)=0

Solution for (8h-3)(4h-7)=0 equation:

(8h-3)(4h-7)=0

We multiply parentheses ..

(+32h^2-56h-12h+21)=0

We get rid of parentheses

32h^2-56h-12h+21=0

We add all the numbers together, and all the variables

32h^2-68h+21=0

a = 32; b = -68; c = +21;
Δ = b2-4ac
Δ = -682-4·32·21
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-68)-44}{2*32}=\frac{24}{64}
=3/8
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-68)+44}{2*32}=\frac{112}{64}
=1+3/4
$