(9u-5)(u-1)=0

Solution for (9u-5)(u-1)=0 equation:

(9u-5)(u-1)=0

We multiply parentheses ..

(+9u^2-9u-5u+5)=0

We get rid of parentheses

9u^2-9u-5u+5=0

We add all the numbers together, and all the variables

9u^2-14u+5=0

a = 9; b = -14; c = +5;
Δ = b2-4ac
Δ = -142-4·9·5
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-4}{2*9}=\frac{10}{18}
=5/9
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+4}{2*9}=\frac{18}{18}
=1
$