(81x-36)(81x+36)=0

Solution for (81x-36)(81x+36)=0 equation:

(81x-36)(81x+36)=0

We use the square of the difference formula

6561x^2-1296=0

a = 6561; b = 0; c = -1296;
Δ = b2-4ac
Δ = 02-4·6561·(-1296)
Δ = 34012224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{34012224}=5832$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-5832}{2*6561}=\frac{-5832}{13122}
=-4/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+5832}{2*6561}=\frac{5832}{13122}
=4/9
$