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(x+4)(x+4)=144(3.14)
We move all terms to the left:
(x+4)(x+4)-(144(3.14))=0
We add all the numbers together, and all the variables
(x+4)(x+4)-452.16=0
We multiply parentheses ..
(+x^2+4x+4x+16)-452.16=0
We get rid of parentheses
x^2+4x+4x+16-452.16=0
We add all the numbers together, and all the variables
x^2+8x-436.16=0
a = 1; b = 8; c = -436.16;
Δ = b2-4ac
Δ = 82-4·1·(-436.16)
Δ = 1808.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-\sqrt{1808.64}}{2*1}=\frac{-8-\sqrt{1808.64}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+\sqrt{1808.64}}{2*1}=\frac{-8+\sqrt{1808.64}}{2} $
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