(8/x+4)-(3/3x+12)

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Solution for (8/x+4)-(3/3x+12) equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

8/x-((3/3)*x)-12+4 = 0

8/x-x-12+4 = 0

8*x^-1-1*x^1-8*x^0 = 0

(8*x^0-1*x^2-8*x^1)/(x^1) = 0 // * x^2

x^1*(8*x^0-1*x^2-8*x^1) = 0

x^1

8-x^2-8*x = 0

8-x^2-8*x = 0

DELTA = (-8)^2-(-1*4*8)

DELTA = 96

DELTA > 0

x = (96^(1/2)+8)/(-1*2) or x = (8-96^(1/2))/(-1*2)

x = (4*6^(1/2)+8)/(-2) or x = (8-4*6^(1/2))/(-2)

x in { (4*6^(1/2)+8)/(-2), (8-4*6^(1/2))/(-2)}

x in { (4*6^(1/2)+8)/(-2), (8-4*6^(1/2))/(-2) }

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