8/3x+10=9/x

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Solution for 8/3x+10=9/x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(8/3)*x+10 = 9/x // - 9/x

(8/3)*x-(9/x)+10 = 0

(8/3)*x-9*x^-1+10 = 0

8/3*x^1-9*x^-1+10*x^0 = 0

(8/3*x^2+10*x^1-9*x^0)/(x^1) = 0 // * x^2

x^1*(8/3*x^2+10*x^1-9*x^0) = 0

x^1

(8/3)*x^2+10*x-9 = 0

(8/3)*x^2+10*x-9 = 0

DELTA = 10^2-(-9*4*(8/3))

DELTA = 196

DELTA > 0

x = (196^(1/2)-10)/(2*(8/3)) or x = (-196^(1/2)-10)/(2*(8/3))

x = 3/4 or x = -9/2

x in { -9/2, 3/4} 

x in { -9/2, 3/4 }

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