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(8/x+2)-(5/x+3)=(3/x+1)
We move all terms to the left:
(8/x+2)-(5/x+3)-((3/x+1))=0
Domain of the equation: x+2)!=0
x∈R
Domain of the equation: x+3)!=0
x∈R
Domain of the equation: x+1))!=0We get rid of parentheses
x∈R
8/x-5/x-((3/x+1))+2-3=0
We calculate fractions
(-5x)/x^2+(-((3*x)/x^2+2-3=0
We add all the numbers together, and all the variables
(-5x)/x^2+(-((+3x)/x^2+2-3=0
We calculate fractions
We do not support expression: x^4
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