(4x-7)(4x-7)=0

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Solution for (4x-7)(4x-7)=0 equation: 



(4x-7)(4x-7)=0

We multiply parentheses ..

(+16x^2-28x-28x+49)=0

We get rid of parentheses

16x^2-28x-28x+49=0

We add all the numbers together, and all the variables

16x^2-56x+49=0

a = 16; b = -56; c = +49;
Δ = b2-4ac
Δ = -562-4·16·49
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{56}{32}=1+3/4$

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