(8/3)y-6=58

Solution for (8/3)y-6=58 equation:

(8/3)y-6=58

We move all terms to the left:

(8/3)y-6-(58)=0


Domain of the equation: 3)y!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

(+8/3)y-6-58=0

We add all the numbers together, and all the variables

(+8/3)y-64=0

We multiply parentheses

8y^2-64=0

a = 8; b = 0; c = -64;
Δ = b2-4ac
Δ = 02-4·8·(-64)
Δ = 2048
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2048}=\sqrt{1024*2}=\sqrt{1024}*\sqrt{2}=32\sqrt{2}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32\sqrt{2}}{2*8}=\frac{0-32\sqrt{2}}{16}
=-\frac{32\sqrt{2}}{16}
=-2\sqrt{2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32\sqrt{2}}{2*8}=\frac{0+32\sqrt{2}}{16}
=\frac{32\sqrt{2}}{16}
=2\sqrt{2}
$