(8-3)x=(16x+1)/2

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Solution for (8-3)x=(16x+1)/2 equation: 



(8-3)x=(16x+1)/2

We move all terms to the left:

(8-3)x-((16x+1)/2)=0

We add all the numbers together, and all the variables

5x-((16x+1)/2)=0

We multiply all the terms by the denominator


5x*2)-((16x+1)=0

Wy multiply elements

10x^2=0

a = 10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·10·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{20}=0$

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