3x(x+20)60=180

Solution for 3x(x+20)60=180 equation:

3x(x+20)60=180

We move all terms to the left:

3x(x+20)60-(180)=0

We multiply parentheses

180x^2+3600x-180=0

a = 180; b = 3600; c = -180;
Δ = b2-4ac
Δ = 36002-4·180·(-180)
Δ = 13089600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{13089600}=\sqrt{129600*101}=\sqrt{129600}*\sqrt{101}=360\sqrt{101}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3600)-360\sqrt{101}}{2*180}=\frac{-3600-360\sqrt{101}}{360}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3600)+360\sqrt{101}}{2*180}=\frac{-3600+360\sqrt{101}}{360}
$