(8)/(9)(3i+27)=(2)/(9)i+68

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Solution for (8)/(9)(3i+27)=(2)/(9)i+68 equation: 



(8)/(9)(3i+27)=(2)/(9)i+68

We move all terms to the left:

(8)/(9)(3i+27)-((2)/(9)i+68)=0



Domain of the equation: 9(3i+27)!=0

i∈R





Domain of the equation: 9i+68)!=0

i∈R



We get rid of parentheses

8/9(3i+27)-2/9i-68=0

We calculate fractions


72i/(243i^2+2187i)+(-18i3/(243i^2+2187i)-68=0

We calculate fractions

We do not support eipression: i^3

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