7/10x+3=-10/7x+20

Solution for 7/10x+3=-10/7x+20 equation:

7/10x+3=-10/7x+20

We move all terms to the left:

7/10x+3-(-10/7x+20)=0


Domain of the equation: 10x!=0

x!=0/10

x!=0

x∈R



Domain of the equation: 7x+20)!=0

x∈R


We get rid of parentheses

7/10x+10/7x-20+3=0

We calculate fractions


49x/70x^2+100x/70x^2-20+3=0

We add all the numbers together, and all the variables

49x/70x^2+100x/70x^2-17=0

We multiply all the terms by the denominator


49x+100x-17*70x^2=0

We add all the numbers together, and all the variables

149x-17*70x^2=0

Wy multiply elements

-1190x^2+149x=0

a = -1190; b = 149; c = 0;
Δ = b2-4ac
Δ = 1492-4·(-1190)·0
Δ = 22201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{22201}=149$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(149)-149}{2*-1190}=\frac{-298}{-2380}
=149/1190
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(149)+149}{2*-1190}=\frac{0}{-2380}
=0
$