(7y-2)+(3y+12)=180

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Solution for (7y-2)+(3y+12)=180 equation: 



(7y-2)+(3y+12)=180

We move all terms to the left:

(7y-2)+(3y+12)-(180)=0

We get rid of parentheses

7y+3y-2+12-180=0

We add all the numbers together, and all the variables

10y-170=0

We move all terms containing y to the left, all other terms to the right

10y=170

y=170/10

y=17

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