(4x+1)=(8x-1)

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Solution for (4x+1)=(8x-1) equation: 



(4x+1)=(8x-1)

We move all terms to the left:

(4x+1)-((8x-1))=0

We get rid of parentheses

4x-((8x-1))+1=0



We calculate terms in parentheses: -((8x-1)), so:

(8x-1)

We get rid of parentheses

8x-1

Back to the equation:

-(8x-1)



We get rid of parentheses

4x-8x+1+1=0

We add all the numbers together, and all the variables

-4x+2=0

We move all terms containing x to the left, all other terms to the right

-4x=-2

x=-2/-4

x=1/2

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