(7y-11)=3(y+1)

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Solution for (7y-11)=3(y+1) equation: 



(7y-11)=3(y+1)

We move all terms to the left:

(7y-11)-(3(y+1))=0

We get rid of parentheses

7y-(3(y+1))-11=0



We calculate terms in parentheses: -(3(y+1)), so:

3(y+1)

We multiply parentheses

3y+3

Back to the equation:

-(3y+3)



We get rid of parentheses

7y-3y-3-11=0

We add all the numbers together, and all the variables

4y-14=0

We move all terms containing y to the left, all other terms to the right

4y=14

y=14/4

y=3+1/2

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