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(1)(3x+3)+(1)/(x+1)=(1)/(6)
We move all terms to the left:
(1)(3x+3)+(1)/(x+1)-((1)/(6))=0
Domain of the equation: (x+1)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
x!=-1
x∈R
1(3x+3)+1/(x+1)-(+1/6)=0
We get rid of parentheses
1(3x+3)+1/(x+1)-1/6=0
We calculate fractions
There is no solution for this equation
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