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(7x-8)(6x+1)-(7x-8)(3x-4)=0
We multiply parentheses ..
(+42x^2+7x-48x-8)-(7x-8)(3x-4)=0
We get rid of parentheses
42x^2+7x-48x-(7x-8)(3x-4)-8=0
We multiply parentheses ..
42x^2-(+21x^2-28x-24x+32)+7x-48x-8=0
We add all the numbers together, and all the variables
42x^2-(+21x^2-28x-24x+32)-41x-8=0
We get rid of parentheses
42x^2-21x^2+28x+24x-41x-32-8=0
We add all the numbers together, and all the variables
21x^2+11x-40=0
a = 21; b = 11; c = -40;
Δ = b2-4ac
Δ = 112-4·21·(-40)
Δ = 3481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3481}=59$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-59}{2*21}=\frac{-70}{42} =-1+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+59}{2*21}=\frac{48}{42} =1+1/7 $
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