5+4(5x-5)=7-3(2x+1)

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Solution for 5+4(5x-5)=7-3(2x+1) equation: 



5+4(5x-5)=7-3(2x+1)

We move all terms to the left:

5+4(5x-5)-(7-3(2x+1))=0

We multiply parentheses

20x-(7-3(2x+1))-20+5=0



We calculate terms in parentheses: -(7-3(2x+1)), so:

7-3(2x+1)

determiningTheFunctionDomain
-3(2x+1)+7

We multiply parentheses

-6x-3+7

We add all the numbers together, and all the variables

-6x+4

Back to the equation:

-(-6x+4)



We add all the numbers together, and all the variables

20x-(-6x+4)-15=0

We get rid of parentheses

20x+6x-4-15=0

We add all the numbers together, and all the variables

26x-19=0

We move all terms containing x to the left, all other terms to the right

26x=19

x=19/26

x=19/26

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