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(7x-8)(3x-20)=0
We multiply parentheses ..
(+21x^2-140x-24x+160)=0
We get rid of parentheses
21x^2-140x-24x+160=0
We add all the numbers together, and all the variables
21x^2-164x+160=0
a = 21; b = -164; c = +160;
Δ = b2-4ac
Δ = -1642-4·21·160
Δ = 13456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{13456}=116$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-164)-116}{2*21}=\frac{48}{42} =1+1/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-164)+116}{2*21}=\frac{280}{42} =6+2/3 $
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