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2(a-1)+2(a+3)=3(a-1)+a
We move all terms to the left:
2(a-1)+2(a+3)-(3(a-1)+a)=0
We multiply parentheses
2a+2a-(3(a-1)+a)-2+6=0
We calculate terms in parentheses: -(3(a-1)+a), so:We add all the numbers together, and all the variables
3(a-1)+a
We add all the numbers together, and all the variables
a+3(a-1)
We multiply parentheses
a+3a-3
We add all the numbers together, and all the variables
4a-3
Back to the equation:
-(4a-3)
4a-(4a-3)+4=0
We get rid of parentheses
4a-4a+3+4=0
We add all the numbers together, and all the variables
7!=0
There is no solution for this equation
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