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(7x-5=2x+23)
We move all terms to the left:
(7x-5-(2x+23))=0
We calculate terms in parentheses: +(7x-5-(2x+23)), so:We get rid of parentheses
7x-5-(2x+23)
determiningTheFunctionDomain 7x-(2x+23)-5
We get rid of parentheses
7x-2x-23-5
We add all the numbers together, and all the variables
5x-28
Back to the equation:
+(5x-28)
5x-28=0
We move all terms containing x to the left, all other terms to the right
5x=28
x=28/5
x=5+3/5
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