2k-2/5=-2k-6

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Solution for 2k-2/5=-2k-6 equation: 



2k-2/5=-2k-6

We move all terms to the left:

2k-2/5-(-2k-6)=0

We get rid of parentheses

2k+2k+6-2/5=0

We multiply all the terms by the denominator


2k*5+2k*5-2+6*5=0

We add all the numbers together, and all the variables

2k*5+2k*5+28=0

Wy multiply elements

10k+10k+28=0

We add all the numbers together, and all the variables

20k+28=0

We move all terms containing k to the left, all other terms to the right

20k=-28

k=-28/20

k=-1+2/5

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