(7x-4)/6=(2x+1)/4

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Solution for (7x-4)/6=(2x+1)/4 equation: 



(7x-4)/6=(2x+1)/4

We move all terms to the left:

(7x-4)/6-((2x+1)/4)=0

We calculate fractions


7x/()+(-((2x+1)*6)/()=0



We calculate terms in parentheses: +(-((2x+1)*6)/(), so:

-((2x+1)*6)/(

We multiply all the terms by the denominator


-((2x+1)*6)



We calculate terms in parentheses: -((2x+1)*6), so:

(2x+1)*6

We multiply parentheses

12x+6

Back to the equation:

-(12x+6)



We get rid of parentheses

-12x-6

Back to the equation:

+(-12x-6)



We get rid of parentheses

7x/()-12x-6=0

We multiply all the terms by the denominator


7x-12x*()-6*()=0

We add all the numbers together, and all the variables

7x-12x*()=0

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