1/3(9c-18-3c)=1/4(12c

Solution for 1/3(9c-18-3c)=1/4(12c equation:

1/3(9c-18-3c)=1/4(12c

We move all terms to the left:

1/3(9c-18-3c)-(1/4(12c)=0


Domain of the equation: 3(9c-18-3c)!=0

c∈R



Domain of the equation: 412c!=0

c!=0/412

c!=0

c∈R


We add all the numbers together, and all the variables

1/3(6c-18)-(1/412c=0

We calculate fractions


412c/(7416c^2-22248c)+(-3c6/(7416c^2-22248c)=0


We calculate terms in parentheses: +(-3c6/(7416c^2-22248c), so:

-3c6/(7416c^2-22248c

We multiply all the terms by the denominator


-3c6

We add all the numbers together, and all the variables

-3c^6

We do not support ecpression: c^6