(7x-4)+(10x=3)+19=52

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Solution for (7x-4)+(10x=3)+19=52 equation: 



(7x-4)+(10x=3)+19=52

We move all terms to the left:

(7x-4)+(10x-(3)+19)=0

We add all the numbers together, and all the variables

(7x-4)+(10x+16)=0

We get rid of parentheses

7x+10x-4+16=0

We add all the numbers together, and all the variables

17x+12=0

We move all terms containing x to the left, all other terms to the right

17x=-12

x=-12/17

x=-12/17

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